At low $ ext{pH}$, how does the dissolution of an amphoteric hydroxide like $ ext{Al}( ext{OH})_3$ proceed?

Answer

The excess $ ext{H}^+$ ions neutralize the hydroxide ion ($ ext{OH}^-$).

In acidic conditions, the $ ext{H}^+$ reacts with the $ ext{OH}^-$ released from the dissolving solid ($ ext{Al}( ext{OH})_3(s) + 3 ext{H}^+ ightleftharpoons ext{Al}^{3+} + 3 ext{H}_2 ext{O}$), causing the solid to dissolve as the $ ext{pH}$ drops.

At low $	ext{pH}$, how does the dissolution of an amphoteric hydroxide like $	ext{Al}(	ext{OH})_3$ proceed?
ChemistryacidBasepHsolubility