What quantity is represented by the slope ($m$) when plotting $\ln(k)$ against $1/T$ in the linearized Arrhenius equation?
Answer
$-E_a/R$
The linearized Arrhenius equation, $\ln(k) = \ln(A) - \frac{E_a}{R} (\frac{1}{T})$, matches the linear form $y = b + mx$, meaning the slope ($m$) must equal the term multiplying $1/T$, which is $-E_a/R$.
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