According to the Stefan-Boltzmann Law, what causes the Red Giant phase to be vastly more luminous than the Main Sequence star?

Answer

The massive increase in surface area ($A$) overwhelms the drop in surface temperature ($T$).

Luminosity is proportional to surface area multiplied by the fourth power of absolute temperature ($L \propto A T^4$). Even though the temperature drops, the enormous expansion leads to a vast increase in surface area, dominating the equation and resulting in higher total luminosity.

According to the Stefan-Boltzmann Law, what causes the Red Giant phase to be vastly more luminous than the Main Sequence star?
astronomystarsstellar evolutionred giantsLuminositymain sequence stars