Under what condition does a collapsing stellar core inevitably form a black hole?
Answer
The remaining core mass exceeds the limit capable of being supported by neutron degeneracy pressure
If the remnant iron core mass is too great, even the immense force of neutron degeneracy pressure cannot stop the collapse. The gravitational compression continues indefinitely, resulting in the formation of a black hole.
Frequently Asked Questions
What primary nuclear reaction characterizes a star's stable main sequence phase?Following hydrogen depletion in the core, what immediately causes the inert helium core to begin contracting?What is the primary energy source that drives the massive expansion of the outer layers into the Red Giant phase?What causes a star transitioning from the main sequence to become a Red Giant?In stars below about 2.2 solar masses, what condition makes the onset of helium fusion an explosive "Helium Flash"?What is the final remnant left behind by a low or intermediate mass star, like the Sun, after the Red Giant phase concludes?What element marks the absolute end of energy-releasing fusion for stars significantly more massive than the Sun?Why does the formation of an iron core trigger an instantaneous, catastrophic collapse in a massive star?What mechanism successfully halts the core collapse to form a neutron star after a Type II Supernova?Under what condition does a collapsing stellar core inevitably form a black hole?How long did a star like our Sun spend on the main sequence compared to its subsequent Red Giant phase?