How is the intensity of scattered light related to wavelength ($\lambda$) in Rayleigh scattering?
Answer
Inversely proportional to the fourth power of the wavelength (Intensity $\propto 1 / \lambda^4$)
Rayleigh scattering is highly dependent on the wavelength, specifically being inversely proportional to the fourth power of the wavelength, meaning shorter wavelengths are scattered much more effectively.
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