For sodium chloride ($ ext{NaCl}$), which dissociates into two ions, what is its theoretical van't Hoff factor ($i$)?
Answer
Theoretically 2
Since $ ext{NaCl}$ splits into $ ext{Na}^+$ and $ ext{Cl}^-$, it contributes twice the number of particles compared to a non-dissociating substance, giving it a theoretical van't Hoff factor of 2.
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