For a wind instrument tube that is closed at one end, what is a direct consequence on the harmonics produced?
Answer
It produces only odd harmonics, and its fundamental frequency is an octave lower than a similarly sized open pipe.
A closed pipe must have a displacement node (no movement) at the closed end, which restricts the possible standing waves to only those resulting in odd harmonics, leading to a lower fundamental frequency compared to an open pipe of the same length.
Related Questions
What condition must be met for acoustic resonance to cause preferential amplification of sound waves?What three physical properties entirely determine an object's natural frequency?In the operation of an empty bottle acting as a Helmholtz resonator, how is acoustic energy exchanged?What does a high Q-factor signify regarding a resonator's behavior?Which mechanism describes energy loss quantified by damping?For a wind instrument tube that is closed at one end, what is a direct consequence on the harmonics produced?What historical electronic components form the basis of a tuned circuit used for frequency selection?To achieve a lower fundamental frequency ($f$) in a simple string fixed at both ends, what must be done according to the formula $f = v / (2L)$?What is the approximate speed of sound ($v$) in dry air at $20^ ext{ extdegree C}$?What phrase encapsulates the ultimate role of resonance in defining the character of sound, as highlighted by composers using reverberant spaces?