By what factor does solar radiation intensity decrease when moving from Earth's orbit (1 AU) to the Kuiper Belt (50 AU)?
Answer
By the square of the distance (1/2500)
The intensity of solar radiation drops off by the square of the distance from the Sun. Therefore, at 50 AU, the heat input is 1/(50^2), or 1/2500th of what is received at 1 AU.
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